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a point charge q is placed at the center of an uncharged conducting shell of inner radius R and outer radius 2R. if the point charge is removed from the centre of the shell, to infinity work done by electric force

2 years ago

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$\small V_{\infty}=0\\ V_{inside}=(-Q/4\pi \epsilonR +Q/4\pi \epsilon2R)=-Q/4\pi \epsilon2R$
Because charge appearing on the inner surface will be -Q and since the charge was originally zero so charge on outside =+Q.
$\small W=-\Delta V \\=>W=-(V_{\infty}-V_0)=V_{0}$
Thanks & Regards
Arun Kumar
IIT Delhi
one year ago

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