```                   a point charge q is placed at the center of an uncharged conducting shell of inner radius R and outer radius 2R. if the point charge is removed from the centre of the shell, to infinity work done by electric force
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```                                        $\small V_{\infty}=0\\ V_{inside}=(-Q/4\pi \epsilonR +Q/4\pi \epsilon2R)=-Q/4\pi \epsilon2R$Because charge appearing on the inner surface will be -Q and since the charge was originally zero so charge on outside =+Q.$\small W=-\Delta V \\=>W=-(V_{\infty}-V_0)=V_{0}$Thanks & RegardsArun KumarIIT DelhiAskiitians Faculty
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2 months ago

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