Use Coupon: CART20 and get 20% off on all online Study Material

Total Price: R

There are no items in this cart.
Continue Shopping
Get instant 20% OFF on Online Material.
coupon code: MOB20 | View Course list

  • Complete Physics Course - Class 11
  • OFFERED PRICE: R 2,800
  • View Details
Get extra R 700 off


when a point charge is suspended at point of suspension of a pendulam given same charge ,what is the time period of pendulum

6 years ago


Answers : (1)


Dear Madhu

only presence of charge will not effect the time period

if there is electric field then it will affect the time period.

suppose a electric field E is acting vertically upword direction

then mg-qE is the resultant force in verticle direction

net acceleration g'=g-qE/m

Time period T=2∏√l/g'


Please feel free to post as many doubts on our discussion forum as you can.
 If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly.
 We are all IITians and here to help you in your IIT JEE  & AIEEE preparation.

 All the best.
Askiitians Experts


6 years ago

Post Your Answer

Other Related Questions on Electrostatics

I want the solution of this question.pls help me sir
Question not available.
Vijay Mukati one year ago
please can i get explanation to the concept behind the question..
Saurabh Kumar 4 months ago
@ amit the question deals with the electric field intensity in a spherical chrged shell . u can calculate it by applying the formula E= RHO *I / 3 E0 where e0 is the permittivity of free...
Umakant biswal 4 months ago
Two points P and Q are maintained at a potential of 10V and -4V respectively.The work done in moving 100 electrons from P to Q is?
Work done = q*(change in potential at those 2 points). = 1.602 x 10^-19 * ( 10 – -4) = 1.602 x 10^-19 x 14 Joule. this is for one electron, As work is the scalar quantity, Total work done = ...
Vikas TU 25 days ago
Ans this question,its urgent...give proper explanation,,by solving it A to Z
@ navya this is a typical simple ques from rain and umbrella problem with respect to man . i am solving that below rain has x comp v cos 30 and y comp v sin 30. when he runs at 4 km/hr,...
Umakant biswal 2 months ago
A ball is thrown vertically upwards from the top of a tower with a speed of 100m/ strikes the pound near the base of the tower after 25sec . The height of the tower is
Hi let us suppose the total height of the tower =h and hence by appling the equation of motion s=ut+(1/2)*a*t 2 by substituting the vaues (–h) = 100*25 + (1/2)(–g)(25) 2 (taking above as...
Ankit Jaiswal one month ago
on taking g as 9.8 our answer will be 562.5m plz approve both if u found them helpful thanks.....................................................
Ankit Jaiswal one month ago
The ball would reach at top of tower at time, T = 2u/g = 2*100/10 = 20 s. that means to cover the height it take 5 seconds. velocity at the top of tower on returning would be: v =100 – g*20 ...
Vikas TU one month ago
View all Questions »

  • Complete Physics Course - Class 12
  • OFFERED PRICE: R 2,600
  • View Details
Get extra R 650 off

  • Complete Physics Course - Class 11
  • OFFERED PRICE: R 2,800
  • View Details

Get extra R 700 off

More Questions On Electrostatics

Ask Experts

Have any Question? Ask Experts

Post Question

Answer ‘n’ Earn
Attractive Gift
To Win!!!
Click Here for details