a ring of radius 0.1 m is made out of thin metallic wire of area of cross section 10^-6 . the ring has uniform charge of pie couloumbs. find the change in the radius of the ring when a charge of 10^-8 coulomb is placed at the centre of the ring. Y = 2 into 10^11

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Sher Mohammad · Answer

the change can be found using log error formula, use it for youngs modulus formula, sher mohammad faculty askiitians b.tech iit delhi

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a ring of radius 0.1 m is made out of thin metallic wire of area of cross section 10^-6 . the ring has uniform charge of pie couloumbs. find the change in the radius of the ring when a charge of 10^-8 coulomb is placed at the centre of the ring. Y = 2 into 10^11

a ring of radius 0.1 m is made out of thin metallic wire of area of cross section 10^-6 . the ring has uniform charge of pie couloumbs. find the change in the radius of the ring when a charge of 10^-8 coulomb is placed at the centre of the ring. Y = 2 into 10^11

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a ring of radius 0.1 m is made out of thin metallic wire of area of cross section 10^-6 . the ring has uniform charge of pie couloumbs. find the change in the radius of the ring when a charge of 10^-8 coulomb is placed at the centre of the ring. Y = 2 into 10^11

a ring of radius 0.1 m is made out of thin metallic wire of area of cross section 10^-6 . the ring has uniform charge of pie couloumbs. find the change in the radius of the ring when a charge of 10^-8 coulomb is placed at the centre of the ring. Y = 2 into 10^11

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