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ravi kumar Mathanya Grade: 12th Pass
        Force between two charge
4 years ago

Answers : (1)

Aman Bansal
592 Points
										

Dear Ravi,


F = Qq/4πεr^2
q , Q - two charges
r - distances between charges
1/4πε - the constant of equation which is 9 x 10^9
F = (2 x 10^-4)(8 x 10^-4)(9 x 10^9)/((0.3)^2)
= 16 000 N


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Aman Bansal


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4 years ago
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