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'n' drops of same size are charged to potential V volts each. if ther are added up to form a single drop then its potential will be.?
For 1 drop, V=kq/r..(r=radius of each drop)
therefore,q=Vr/k....for 1 drop
if we have n drops, total charge=Q=nq=Vrn/k
total radius=R=rn^.33...(apply volume conservation)
V=kQ/R=kVrn/k(rn^.33)=Vn^.66(Ans.)
Hope this helps.
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