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pallavi pradeep bhardwaj Grade: 12
        A drop of liquid of diametre 2.8mm breaks up inti 125 identical drops The change in energy is nearly
7 years ago

Answers : (2)

askiitiansexpert soumyajit_iitkanpur
8 Points
										
										
7 years ago
askiitiansexpert soumyajit_iitkanpur
8 Points
										

let the radius of each droplet be r m


Volume of bigger drop = total volume of 125 droplets


(4/3)* pi * (1.4*10-3)3 = 125 * (4/3) * pi * r3


=> r = (1.4/5)* 10-3 = 0.28*10-3


change in surface area = ds = 4*pi* [125* (0.28*10-3) 2 - (1.4*10-3)2] m


                                       = 0.0984 m


if surface tension of the liquid ne T Nm-1 then work done W = Tds = 0.098T J.

7 years ago
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