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```
An electron is shot at an initial speed of V0  m/s, at an angle theta  from the x-axis. It moves through a uniform electric field E j^ . A screen for detecting electrons is positioned parallel to the y-axis , ata a distance x'. What is the velocity of the electron when it hits the screen.?

```

7 years ago

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```										hi,
x component of velocity = V0 cos θ
accleration in x direction is zer0
x component of velocity after tsec , v1x =  V0 cos θ ,
& time taken to reach the sc reen ,t =  x'/ V0 cos θ
vertical component of velocity = V0 sin θ  & accl. = -eE /m
vertical velocity at time  t  ,  v1y  =   V0 sin θ  -  eE /m  * x'/ V0 cos θ
=   V0 sin θ  -  eE  x'/ mV0 cos θ
velocity after time t ,v1  = √ v1x^2  + v1y ^2
=  √   {  V0 cos θ)^2  + ( V0 sin θ  -  eE  x'/ mV0 cos θ  )^2 }
```
7 years ago

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