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Saneet Satish Agrawal Grade: 12
        

Two small spheres having same mass and charge are loacated at the same vertical line at heights h1 and h2(h2>h1). They both are thrown simultaneously with the same velocity V in the same direction along the horizontal. From the initial vertical line, the first sphere hits the ground ata distance l. Then at this instance height of second ball,H=??


Ans in terms of h1,h2,l,V and g(acc due to gravity)


 

8 years ago

Answers : (1)

piyush garg
9 Points
										

let mass of both the charges is m and charge on both the charges is q


take a sphere which is at height h1 two forces act on it


force of gravitation in downword direction and electrostatic force in downward direction hence net downward direction is qe+mg/m hence accelaration is qe/m+g hence


h1=1/2(g+qe/m)t^2


let t is time taken by small sphere in travelling distance


l=vt , t=l/v


let x is distance travelled by second sphere


forces acting on it


force of gravitation downward and electrostatic force upwards hence net acceleration in downward direction is( g-qe/m)


X=1/2(g-qe/m)t^2


height at this instant is h2-x


x=gl^2/v^2-h1


hence height is h2-(gl^2/v^2)

8 years ago
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