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it is a basic question of the GAUSS LAW. Simply apply the Gauss Law at the two cylindrical gausian surfaces having its axis same as the cylinders and the radius 4 and 8 cms respectively. In case of second the total charge wud be -2 micro coulumb. See the length of the hollow cylinde does not matter . Hope u understand why!!!!!!!!1
Hi
Acc to gauss law, electric field wud be only because of the charge enclosed.
Gauss's law, also known as Gauss's flux theorem, is a law relating the distribution of electric charge to the resulting electric field. Gauss's law states that:
In integral form the equation is:
In this case , for r=4cm , electric field will be only because of the inner cylinder , bcoz as we draw the gaussian surface outside the inner cylinder but inside the outer cyl, the charge enclosed is just 5x10-6 . So, in the gauss law, put q enclosed equal to 5x10-6 . .
In second case, draw gaussian surface outside the second cyl, hence net charge enclosed is now the sum of the two charges , hence the net q enclosed is ( -2x 10-6 ), use this in the eq and find E.
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