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`        in the formula, V= kq/r, what is k, q and r . Pls explain where and why is this formula usd and show the derivation too!!!!!! Pls!!!!!`
6 years ago

510 Points
```										V = potential at any point ...
V = kq/r
another definition =>  workdone in bringing +ve test charge(q=1)  from infinity to a point which is at a distance r , near a charge q ...
F = k(q)(qo)/r2                      (from culambs law)
qo is +ve test charge , F is force bw test charge & q charge...
F = -dU/dr
dU/dr = -F = -kqqo/r2
dU = -kqqo(1/r2)dr             lim from infinity to r
U = -kqqo(-1/r)                 lim infinity to r                     [   (1/r2)dr = -1/r     ]
U = kqqo/r                  (qo = 1)
so , U = kq/r
here K is columbs constant , k = 9*109units , q is charge ...
this is the required result...
```
6 years ago
510 Points
```										approve if u like my ans
```
6 years ago
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