Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-5470-145
+91 7353221155
Use Coupon: CART20 and get 20% off on all online Study Material
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
OTP to be sent to Change
Suppose a disc of radius a placed on the groung with uniform surface charge density s with its axis vertical.A charged particle is dropped from a height H from the ground along the axis of the disc.Initially the particl is at rest so initial kinetic energy is equal to zero.Then see the point when the electric force on the particle is equal to the gravitational force.At that point velocity of the particle is zero.Hence the change in kinetic energy is equal to zero.So the work done by the net external force should be zero.But the resultant force is causing a net displacement in the downward direction.So there has to be some work done by the net external force.Please explain this.
dear vinay ,
particle is dropped from height H ... electric field due to disk is upward so the force acting on
particle is in upward direction....
gravitational pull by earth is always constant = mg(downward)....
work due to elctric field & gravity is of opposite sign ,
Wg + We = KE change (0)
Wg = -We
Dear sir
That is what I am saying.If work done by the gravitational force is negative of the work done by the electric force then the net work should be zero.But as there is net displacement there has to be net work done.Please explai this one.
Get your questions answered by the expert for free
You will get reply from our expert in sometime.
We will notify you when Our expert answers your question. To View your Question
Win Gift vouchers upto Rs 500/-
Register Yourself for a FREE Demo Class by Top IITians & Medical Experts Today !