MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: R

There are no items in this cart.
Continue Shopping
Menu
Get instant 20% OFF on Online Material.
coupon code: MOB20 | View Course list

  • Complete Physics Course - Class 11
  • OFFERED PRICE: R 2,800
  • View Details
Get extra R 560 off
USE CODE: MOB20

				   if in capacitance no heat loss is possible if we apply ac why donot be use capacitors instead of resistors
				   

7 years ago

Share

Answers : (2)

										

 


Resistors arnt used!!


It is like a package with the wires tht we cannot remove.


In some cases where heating is required, as in heaters, we do use resisitors.


Also some resistance is essential as if R==0 exaclty then in case of resonance, w=(LC)(0.5), there will be very high current tht may damage the circuits and devices.


 

7 years ago
										

hi piyush,


 another reasons for not using capacitor instead of resistor might be dat when we use capacitor den it wud cause a phase difference inside d circuit n dis is n't desirable in any system....i think u already know abt dis property of capacitor dat it causes a phase difference of pi/2...



capacitor phase diag


consider  a circuit which has only a capacitor and an AC power source (such as a wall outlet). A capacitor is a device for storing charging. It turns out that there is a 90° phase difference between the current and voltage, with the current reaching its peak 90° (1/4 cycle) before the voltage reaches its peak. Put another way, the current leads the voltage by 90° in a purely capacitive circuit.


To understand why this is, we should review some of the relevant equations, including:


relationship between voltage and charge for a capacitor: CV = Q



The AC power supply produces an oscillating voltage. We should follow the circuit through one cycle of the voltage to figure out what happens to the current.


Step 1 - At point a (see diagram) the voltage is zero and the capacitor is uncharged. Initially, the voltage increases quickly. The voltage across the capacitor matches the power supply voltage, so the current is large to build up charge on the capacitor plates. The closer the voltage gets to its peak, the slower it changes, meaning less current has to flow. When the voltage reaches a peak at point b, the capacitor is fully charged and the current is momentarily zero.


Step 2 - After reaching a peak, the voltage starts dropping. The capacitor must discharge now, so the current reverses direction. When the voltage passes through zero at point c, it's changing quite rapidly; to match this voltage the current must be large and negative.


Step 3 - Between points c and d, the voltage is negative. Charge builds up again on the capacitor plates, but the polarity is opposite to what it was in step one. Again the current is negative, and as the voltage reaches its negative peak at point d the current drops to zero.


Step 4 - After point d, the voltage heads toward zero and the capacitor must discharge. When the voltage reaches zero it's gone through a full cycle so it's back to point a again to repeat the cycle.


 


7 years ago

Post Your Answer

Other Related Questions on Electrostatics

Can someone help with Q16 that`s in the attachment. Thank you.
 
 
The correct answer for this question is 3C/4. For solving these types of questions, mark the capacitor plates having same voltages and then simplify the circuit diagram by connecting the...
 
Raman Mishra 4 months ago
 
@ ashmeet as in this circuit there are no battery or cell combination . so, this ques becomes easy. just redraw the circuit where 3 of them are in parallely connected . then applying the...
 
Umakant biswal 4 months ago
 
I think the answer will be option d because the first 3 capacitors are undoubtedly parallel but the next 2 capacitors are parallel and finally the first 3 next 2 and the last one are in...
 
Archishman khasnovis 4 months ago
Four identical large metal plates are arranged parallel to each other, with equal gaps in between. They are given charges q, 2q, 3q and 4q (counting from any one side). The outermost plates...
 
 
these are plates or wire first confirm that because in begining u wrote plates then in end it is wire. plz send figure if u have of this question. KINDLY CHECK THIS AGAIN :-))))))))))))
 
prateek 3 months ago
 
Sir here the wire is the one which is used for shor
 
Apurv Sirohi 3 months ago
 
Sir here the wire is the one which is used for
 
Apurv Sirohi 3 months ago
Q1.....A is the correct answer...How?.............????
 
 
VERY EASY QUESTION. +q and -q makes a dipole. SEE ch electrostatics class12. suppose test charge on p. THEN due to +q it was repelled and due to -q it is attracted. then simple laws of...
 
prateek 2 months ago
 
this a very ea
 
prateek 2 months ago
 
well
 
prateek 2 months ago
what is work energy thereom...................................?
 
 
The work-energy theorem is a generalized description of motion which states that work done by the sum of all forces acting on an object is equal to change in that object’s kinetic energy....
 
dolly bhatia one month ago
 
The work W done by the net force on a particle equals the change in the particle`s kinetic energy KE: W = Δ K E = 1 2 m v f 2 − 1 2 m v i 2 . The work-energy theorem can be derived from...
 
Sushmit Trivedi one month ago
 
For any net force acting on a particle moving along any curvilinear path, it can be demonstrated that its work equals the change in the kinetic energy of the particle by a simple derivation...
 
rahul kushwaha 3 months ago
The cieling of long hall is 25 m high What is the maximum horizontal distance that a ball thrown with a speed of 40 ms can go without hitting the ceiling of wall? Plz explain with a DIAGRAM
 
 
Let the angle of throwing be Q with respect to the ground So, the range is R = 40*cosQ*t where t = time taken reach ground. Now, we know the time taken to reach the top of its flight is half...
 
Tapas Khanda 5 months ago
 
Let the angle of throwing be Q with respect to the ground So, the range is R = 30*cosQ*t where t = time taken reach ground. Now, we know the time taken to reach the top of its flight is half...
 
Tapas Khanda 5 months ago
 
Diagram is not required to solve this question. You can directly use the formula to find range : R = (v^2/g)*sin2Q Maximum height reached, H = v^2*sin^2Q/2g So, 25 = 40^2*sin^2Q/(2*9.8) So,...
 
Tapas Khanda 5 months ago
What harmfull gases are produced when we burn plastics? And can we burn plastics?
 
 
I`m doing a project, can someone help me, How to reduce those toxic contents when plantic are burnt Like sulphur, nitrogen etc
 
2017 years ago
 
nitrogen gas , sulphur dioxide ,carbon monoxide , carbon dioxide. are some of the gases. well burning plastic is not good for living things. but there are many other things that are more...
 
4 days ago
View all Questions »

  • Complete Physics Course - Class 12
  • OFFERED PRICE: R 2,600
  • View Details
Get extra R 520 off
USE CODE: MOB20

  • Complete Physics Course - Class 11
  • OFFERED PRICE: R 2,800
  • View Details

Get extra R 560 off
USE CODE: MOB20

More Questions On Electrostatics

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!!
Click Here for details