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Bhanu Kiran Grade: Upto college level
        

Sixty four equal charged drops are combined to form a big drop. If the potential on each drop is 10 volt, then potential on big drop will be...

6 years ago

Answers : (4)

SAGAR SINGH - IIT DELHI
879 Points
										

Dear student,


64 4/3 pie r3=4/3 pie R3


R=4r


Similarly we can find the charge on bigger sphere.


 


Hence potential on bid srop will be 16* 10=160 V


 

6 years ago
vikas askiitian expert
510 Points
										

let the radius of each small drop is r ...


let radius of drop formed after combination of all drops is R..


in this process volume remains same so,


       initial  volume=64(4/3xpi(r)3)............1


       final volume=4/3pi(R)3 ...................2


equating 1 and 2 we get


            R=4r                     ..............3


now potential of small drop is given 10 volts


potential of small drop =Vs=kq/r      (charge of each drop is q)


now potential of big drop=Vb=kQ/R


Q=total charge=64q and R=4r


now Vb=64kq/4r=16kq/r


                     Vb =16Vs


                         =16x10=160volts

6 years ago
Souradeep Majumder
80 Points
										

THE POTENTIAL OF THE BIGGER DROP IS 160 VOLT................  USE THE FORMULA N2/3V


 


APPROVE MY ANSWER...............

6 years ago
Raghunath Yadav Karike
35 Points
										

For one drop V=(4/3)*(3.14)*r^3


For big one V=64*(4/3)*(3.14)*r^3=(4/3)*(3.14)*(r')^3


                       =r'/r=4


        therefore r'=4*r


Potential due to one drop=V=K*q/r


For big drop= V'=K*64*q/r'


                        =K*64*q/(4*r)


                        =16*V


                        =16*10


                        =160 V


This is what I think.

6 years ago
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