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Bhanu Kiran Grade: Upto college level
`        `
7 years ago

## Answers : (1)

vikas askiitian expert
510 Points
```										let the mid point of base is p..
distance of q charge from P is (42 -12)1/2 =sqrt15cm....           (by using pythogorus theorem)
=sqrt15x10-2m
potential due to q charge is Vq= kq/r
= 100kq/sqrt15 ...........1
distance of any -q charge from p is 1cm
potential due to two -q charges at p will be
2V-q = -2x100kq
=-200kq     .........2
net potential is addition of these
VT =  -200kq + 100kq/sqrt15
=1.09x107 V
=
```
7 years ago
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