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3 equal 1.2*10^(-6) point charges placed at the corners of an equallatiral triangle with sides 0.5 m long.What is the elecntial tric potential energy of the system ?
let the vertices of triangle are a,b,c ..
side of the triangle is d...
electric potential energy of system = Kqaqb/d +kqaqc/d +kqbqc/d
qa = qb =qc =q
so PE = 3kq2 /d
=3*9*109 *(1.2*10-6)2 /0.5
=7.76*10-2 joule
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