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`        the electric field 0.4 m from a very long unifoem line of charge is 840 N/C.How much charge is contained in a 2.00 cm section of the line ?`
6 years ago

510 Points
```										let the charge density of line of charge is d..
now we have
electric field by line of charge = 2kd/r      ( k is electrostatic constant =9.109 )
at  0.4m electric field is 840

so,     2kd/0.4=840
d=168/k=(1.86).(10)-8 columb/m
charge density is d so the charge contained by any small portion is d(x)
charge contained in 2cm=(1.86)(2)(10)-10
=3.73(10)-10 columb

```
6 years ago
35 Points
```										Dear Raju,
In this case we have the formula i.e, E=(lambda)/(2pi(Eo)r) ------------------> 1
Determine the value of lambda that is linear charge density from above and apply it for the second case.
By 1 we get the value of lambda.
then to calculate the required charge use **** lambda=charge/length
Then u can easily get the answer
```
6 years ago
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