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raju manga Grade: 12
        

the electric field 0.4 m from a very long unifoem line of charge is 840 N/C.How much charge is contained in a 2.00 cm section of the line ?

6 years ago

Answers : (2)

vikas askiitian expert
510 Points
										

let the charge density of line of charge is d..


now we have


                        electric field by line of charge = 2kd/r      ( k is electrostatic constant =9.109 )


at  0.4m electric field is 840


 


so,     2kd/0.4=840


           d=168/k=(1.86).(10)-8 columb/m


charge density is d so the charge contained by any small portion is d(x)


charge contained in 2cm=(1.86)(2)(10)-10


                                  =3.73(10)-10 columb


 

6 years ago
Raghunath Yadav Karike
35 Points
										

Dear Raju,


In this case we have the formula i.e, E=(lambda)/(2pi(Eo)r) ------------------> 1


Determine the value of lambda that is linear charge density from above and apply it for the second case.


By 1 we get the value of lambda.


then to calculate the required charge use **** lambda=charge/length


Then u can easily get the answer

6 years ago
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