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gOlU g3n|[0]uS Grade: Upto college level
        

Two particles hv equal mass 5g each & opp. charges 4 X 10-5 .They r released frm rest with separation of 1 m b\w them.Find speeds of the particle when the seperation is reduce to 50cm.

6 years ago

Answers : (1)

vikas askiitian expert
510 Points
										

 applying conservation of momentam bw initial and final stage


      Pi=0


      Pf=mv1 +mv2


     Pf=Pi


   v1=-v2..........1


 now applying energy conservation bw two points


 KEi + (P.E)i = KEf  + (P.E)f


(mv1^2 -mv2^2)/2 =kq^2(2/r -1/r )


     mv1^2=154/10


        v1=53.66m/s=-v2


 

6 years ago
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