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NIKHIL GARG Grade: 12
        

Suppose a charge +Q1 is given to the positive plate and a charge -Q2 to the negative plate of a capacitor. What is the "charge on the capacitor" ?

6 years ago

Answers : (1)

Gokul Joshi AskiitiansExpert-IITK
42 Points
										

Dear Nikhil,

By applying gauss law it can easily be proven that inner faces of plates shall have equal charge of opposite magnitudes, say q0 and -q0. Field on the outside of plates will be (Q1-Q2)/2ε0 and this gives charge of (Q1-Q2)/2 on the outer plates from gauss law. This implies inner sides of plates shall have q0 = (Q1+Q2)/2 and -q0 = -(Q1+Q2)/2. Charge on the capacitor hence is (Q1+Q2)/2.

Please feel free to post as many doubts on our discussion forum as you can.we will get you the answer and detailed  solution very  quickly. All the best.

Regards,
Askiitians Experts,
Gokul  Joshi

6 years ago
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