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shalini goyal Grade: 12
        two identical balls of charges Q1 and Q2 initally have equal velocity of d same magnitude and direction.after a uniform electric field is applied for sometym ,the direction of d velocity of d first ball changes by 60. and d magnitude is reduced by half.the direction of d velocity of d second ball changes there by 90. .in what proportion will the velocity of second ball changes???? the curect ans is v/<3>......where<$>...means under-root $...!! give me a curect solution wid a curect explaination!! THanKu... n plz do open my profile.....see the posted ques....n reply 'em.....i dint get reply f d ques i'hv sent
6 years ago

Answers : (1)

Rahul askIITiansExpert.IITR
110 Points
										the solution is fairly simple

the point to be noticed here is the fact that their accelerations will be in the ratio to their charges since F=ma

and F=QE

since the field if uniform

QE=ma

so a=QE/m

a=kQ

now,

write the separate equation of of bothe the charges in x direction

q1=>

Vxi=v, Vxf=V/2cos60=V/4;

so, Vxf=Vxi-a1xT

V/4=V-a1T.................................1

similarly for the charge q2

0=V-a2T.......................................2

using 1 and 2, we get

a1/a2=3/4.......................................3

now write the equation for y direction in the same way

equate a1/a2(in x)=a1/a2(in y)

and get the answer.

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Rahul- IIT Roorkee
6 years ago
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