MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Hrishant Goswami Grade: 10
        When 1.0 × 10^12 electrons are transferred from one conductor to another, a potential difference of 10 V appears between the conductors. Calculate the capacitance of the two-conductor system.
3 years ago

Answers : (1)

Deepak Patra
askIITians Faculty
474 Points
										Sol. Given that

Number of electron = 1 × 10^12
Net charge Q = 1 × 10^12 × 1.6 × 10^–19 = 1.6 × 10^–7 C
∴ The net potential difference = 10 L.
∴ Capacitance – C = q/v = 1.6 * 10^-7/10 = 1.6 * 10^-8 F.
3 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies
  • Complete JEE Main/Advanced Course and Test Series
  • OFFERED PRICE: Rs. 15,000
  • View Details
  • Electricity and Magnetism
  • OFFERED PRICE: Rs. 1,600
  • View Details

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details