MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Radhika Batra Grade: 11
        Two insulating small spheres are rubbed against each other and placed 1 cm apart, If they attract each other with a force of 0.1 N, how many electrons were transferred from one sphere to the other during rubbing?
3 years ago

Answers : (1)

Kevin Nash
askIITians Faculty
332 Points
										Sol. F = 0.1 N

r = 1 cm = 10^–2 (As they rubbed with each other. So the charge on each sphere are equal)
So, F = kq base 1q base 2/r^2 ⇒ 0.1 = kq^2/(10^-2)^2 ⇒ q^2 = 1/9 * 10^-14 ⇒ q = 1/3 * 10^-7
1.6 * 10^-19 c Carries by 1 electron 1 c carried by 1/1.6 * 10^-19
0.33 * 10^-7 c carries by 1/1.6 * 10^-19 * 0.33 * 10^-7 = 0.208 * 10^12 = 2.08 * 10^11
3 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies
  • Complete JEE Main/Advanced Course and Test Series
  • OFFERED PRICE: Rs. 15,900
  • View Details
  • Electricity and Magnetism
  • OFFERED PRICE: Rs. 1,696
  • View Details

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details