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`        The plates of a capacitor of capacitance 10 μF, charged to 60 μC, are joined together by a wire of resistance 10 Ω at t = 0. Find the charge on the capacitor in the circuit at (a) t = 0, (b) t = 30 μs, (c) t = 120 μs and (d) t = 1.0 ms.`
3 years ago

396 Points
```										Sol. C = 10 μF, Q = 60 μC, R = 10 Ω
a) at t = 0, q = 60 μc
b) at t = 30 μs, q = Qe^–t/RC
= 60 * 10^–6 * e^–0.3 = 44 μc
c) at t = 120 μs, q = 60 * 10^–6 * e^–1.2 = 18 μc
d) at t = 1.0 ms, q = 60 * 10^–6 * e^–10 = 0.00272 = 0.003 μc.

```
3 years ago
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