0

Guest

Courses New

The needle of a dip circle shows an apparent dip of 45° in a particular position and 53° when the circle is rotated through 90°. Find the true dip.

The needle of a dip circle shows an apparent dip of 45° in a particular position and 53° when the circle is rotated through 90°. Find the true dip.

Grade:upto college level

1 Answers

Navjyot Kalra
askIITians Faculty 654 Points
9 years ago
Sol. We know B base H = μ base 0in/2r Give : B base H = 3.6 * 10^-5 T θ = 45° i = 10 mA = 10^-2 A tan θ = 1 n = ? r = 10 cm = 0.1 m n = B base H tan θ * 2r/μ base 0i = 3.6 * 10^-5 * 2 * 1 * 10^-1/4π * 10^-7 *10^-2 = 0.5732 * 10^3 = 573 turns

Think You Can Provide A Better Answer ?

Other Related Questions on Electromagnetic Induction

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More