MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Simran Bhatia Grade: 11
        Find the dimensional formula of ε0. 
3 years ago

Answers : (3)

Aditi Chauhan
askIITians Faculty
396 Points
										Sol. ε base 0 = Coulomb^2/Newton m^2 = l^1 M^-1 L^-3 T^4

∴ F = kq base 1q base 2/r^2
3 years ago
Apoorva Arora
IIT Roorkee
askIITians Faculty
181 Points
										
The permittivity of free space is given by
\epsilon _{0}=8.85\times 10^{-12} m^{-3} Kg^{-1}s^{4}A^{2}
so the dimensional formula is
=[M^{-1}L^{-3}T^{4}A^{2}]
Thanks and Regards
Apoorva Arora
IIT Roorkee
askIITians Faculty
3 years ago
Apoorva Arora
IIT Roorkee
askIITians Faculty
181 Points
										

The permittivity of free space is given by


Description: \epsilon _{0}=8.85\times 10^{-12} m^{-3} Kg^{-1}s^{4}A^{2}


so the dimensional formula is


Description: =[M^{-1}L^{-3}T^{4}A^{2}]


Thanks and Regards


Apoorva Arora


IIT Roorkee


askIITians Faculty







3 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies
  • Complete JEE Main/Advanced Course and Test Series
  • OFFERED PRICE: Rs. 15,000
  • View Details
  • Electricity and Magnetism
  • OFFERED PRICE: Rs. 1,600
  • View Details

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details