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Amit Saxena Grade: upto college level
`        Estimate the number of electrons in 100 g of water. How much is the total negative charge on these electrons?`
3 years ago

Navjyot Kalra
654 Points
```										Sol. No. of electrons of 100g water = 10 * 100/18 = 55.5 Nos total charge = 55.5
No. of electrons in 18 g of H base 2O = 6.023 * 10^23 * 10 = 6.023 * 10^24
No. of electrons in 100 g of H base 2O = 6.023 * 24^24 * 100/18 = 0.334 * 10^26 = 3.334 * 10^25
Total charge = 3.34 * 10^25 * 1.6 * 10^-19 = 5.34 * 10^6 c

```
3 years ago
Arun Kumar
IIT Delhi
256 Points
```										Hello$\\n={100 \over 18} \\n={50 \over 9} \\H=2e \\O=8e \\=>H_2O=18e \\=>total_{e}=6.022*10^{23}*18 \\=>total_{charge}=1.67*6.022*10^{23}*18$Thanks & RegardsArun KumarBtech, IIT DelhiAskiitians Faculty
```
3 years ago
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