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`        Assume that each iron atom has a permanent magnetic moment equal to 2 Bohr magnetons (1 Bohr magnetic equals 9.27 × 10^-24 A-m^2). The density of atoms in iron is 8.52 × 10^28 atoms/m^3. (a) Find the maximum magnetization I in a long cylinder of iron. (b) Find the maximum magnetic field B on the axis inside the cylinder.`
3 years ago

396 Points
```										Sol.
f = 8.52 x 10 ^28 atoms / m^3
For maximum ‘I’, Let us consider the no. of atoms present in 1 m^3 of volume.
Given: m per atom = 2 × 9.27 × 10^–24 A–m^2
I = net m / V = 2 × 9.27 × 10^–24 × 8.52 × 10^28 ≈ 1.58 × 10^6 A/m
B = μ0 (H + I) = μ0  [∴ H = 0 in this case]
= 4π × 10^–7 × 1.58 × 10^6 = 1.98 × 10^–1 ≈ 2.0 T

```
3 years ago
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