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Hrishant Goswami Grade: 10
        An average emf of 20 V is induced in an inductor when the current in it is  changed from 2.5 A in one direction to the same value in the opposite direction in 0.1 s. Find the self-inductance of the inductor.
3 years ago

Answers : (1)

Navjyot Kalra
askIITians Faculty
654 Points
										Sol. V = 20 V

dI = I base 2 – I base 1 = 2.5 – (–2.5) = 5A
dt = 0.1 s
V = L dl/dt
⇒ 20 = L(5/0.1) ⇒ 20 = L × 50
⇒ L = 20 / 50 = 4/10 = 0.4 Henry.
3 years ago
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