MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Radhika Batra Grade: 11
         A short magnet produces a deflection of 37° in a deflection magnetometer in Tan-A position when placed at a separation of 10 cm from the needle. Find the ratio of the magnetic moment of the magnet to the earth’s horizontal magnetic field.
3 years ago

Answers : (1)

Kevin Nash
askIITians Faculty
332 Points
										Sol. M/B base H (found in the previous problem) = 3.75 *10^3 A-m^2 T^-1

θ = 37°, d = ?
M/B base H = 4π/μ base 0 (d^2 - ℓ^2)^3/2 tan θ
ℓ << d neglecting ℓ w.r.t.d
⇒ M/B base H = 4π/μ base 0 d^3 Tanθ⇒ 3.75 * 10^3 = 1/10^-7 * d^3 * 0.75
⇒ d^3 = 3.75 * 10^3 * 10^-7/0.75 = 5 * 10^-4
⇒ d = 0.079 m = 7.9 cm
3 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies
  • Complete JEE Main/Advanced Course and Test Series
  • OFFERED PRICE: Rs. 15,900
  • View Details
Get extra Rs. 3,180 off
USE CODE: CART20
  • Electricity and Magnetism
  • OFFERED PRICE: Rs. 1,696
  • View Details
Get extra Rs. 339 off
USE CODE: CART20

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details