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Amit Saxena Grade: upto college level
        A particle having a charge of 2.0 × 10^-8 C and a mass of 2.0 × 10^-10 g is projected with a speed of 2.0 × 10^3 m/s. in a region having a uniform magnetic field of 0.10 T. The velocity is perpendicular to the field. Find the radius of the circle formed by the particle and also the time period.
3 years ago

Answers : (1)

Navjyot Kalra
askIITians Faculty
654 Points
										Sol. q = 2.0 × 10–8 C B ⃗ = 0.10 T

m = 2.0 * 10^-10 g = 2 * 10^-13 g
υ = 2.0 * 10^3 m/’
R = m υ/qB = 2 * 10^-13 *2 * 10^3/2 * 10^-8 * 10^-1 = 0.2 m = 20 cm
T = 2πm/qB = 2 * 3.14 *2 * 10^-13/2 * 10^-18 * 10^-1 = 6.28 * 10^-4 s
3 years ago
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