MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Hrishant Goswami Grade: 10
        A coil having inductance 2.0 H and resistance 20 Ω is connected to a battery of emf 4.0 V. Find (a) the current at the instant 0.20 s after the connection is made and (b) the magnetic field energy at this instant. 
3 years ago

Answers : (1)

Deepak Patra
askIITians Faculty
474 Points
										Sol. L = 2.0 H, R = 20 Ω, emf = 4.0 V, t = 0.20 S

i base 0 = e/R = 4/20, t = L/R = 2/20 = 0.1
(a) i = i base 0 (1 – e^-0.2/0.1)
= 0.17 A
(b) ½ Li^2 = ½ x 2 x (0.17)^2 = 0.0289 = 0.03 J.
3 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies
  • Complete JEE Main/Advanced Course and Test Series
  • OFFERED PRICE: Rs. 15,000
  • View Details
  • Electricity and Magnetism
  • OFFERED PRICE: Rs. 1,600
  • View Details

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details