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`        A capacitor with stored energy 4.0 J is connected with an identical capacitor with no electric field in between. Find the total energy stored in the two capacitors.`
3 years ago

Jitender Pal
365 Points
```										Sol. Stored energy of capacitor C base 1 = 4.0 J
= 1/2 q^2/c^2 = 4.0 J
When then connected, the charge shared
1/2 q base 1^2/c^2 = 1/2 q base 2^2/c^2 ⇒ q base 1 = q base 2
So that the energy should divided.
∴ The total energy stored in the two capacitors each is 2 J.

```
3 years ago
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