Click to Chat

1800-2000-838

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Amit Saxena Grade: upto college level
`        A bar magnet of length 1 cm and cross-sectional area 1.0 cm^2 produces a magnetic field of 1.5 × 10^-4 T at a point in end-on position at a distance 15 cm away from the centre. (a) Find the magnetic moment M of the magnet. (b) Find the magnetization I of the magnet. (c) Find the magnetic field B at the centre of the magnet.`
3 years ago

Navjyot Kalra
654 Points
```										Sol. (a) Given d = 15 cm = 0.15 m
l = 1 cm = 0.01 m
A = 1.0 cm^2 = 1 x 10^-4 m^2
B = 1.5 x 10^-4 T
M = ?
We know B ⃗ = μ base 0/ 4π x  2Md/(d^2 – l^2)^2
⇒ 1.5 x 10^-4 = 10^-7 x 2 x M x 0.15/ (0.02255 – 0.0001)^2 = 3x 10^-8M / 5.01x 10^-4
⇒ M = 1.5 x 10^-4 x 5.01 x 10^-4/3x 10^-8 = 2.5 A
(b) Magnetisation I = M/V = 2.5 / 10^-4 x 10^-2 = 2.5 x 10^6 A/m
(c) H = m/4πd^2 = M/ 4πId^2 = 2.5/ 4 x 3.14 x 0.01 x (0.15)^2
net H = H base N + H = 2 x 884.6 = 8.846 x 10^2
B ⃗ = μ base 0 (-H + I) = 4π x 10^-7 (2.5 x 10^6 – 2 x 884.6) ≈ 3,14 T

```
3 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Electromagnetic Induction

View all Questions »
• Complete JEE Main/Advanced Course and Test Series
• OFFERED PRICE: Rs. 15,900
• View Details
• Electricity and Magnetism
• OFFERED PRICE: Rs. 1,696
• View Details