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A uniform magnetic field of induction B is changing in magnitude at a constant rate dB/dt.  copper wire of mass M is to be drawn into  wire of rdius r and formed into a circular loop of radius R. If P(rho) is the specific resistance and  delta( ) is the density of wire, then what is the induced current in the loop? Assume B is perpendicular to the loop..

6 years ago


Answers : (1)


Dear Saurabh, 

Resistance s=ρl/A,l=2πr, A=πr2, s=2ρR/r2, V= d/dt(πR2B)=πR2dB/dt, current I=V/s =(πRr2/2ρ)(dB/dt)

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