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A non-conducting ring of radius 'r' has charge 'Q'. A magnetic field perpendicular to the plane of th ring changes as dB/dt.the torque experienced by the ring is?
Dear M.vs vivek vardhan,
torque = u*B (this is cross product)
u = the magnetic dipole moment
B =the magnetic field vector u = I*A = (current * area) u x B = u*B*Sin(theta) here theta is 90 and I=dQ/dt
Torque= dQ/dt * B * (Π *r^2) = Q* dB/dt * (Π *r^2)
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