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Siddharth Singhania Grade: 11
        

In the circuit given in the figure the initial value of current through the battery on closing the circuit(i.e. K is pressed) is


ans: 0.3 A


can you please explain how?


832_21201_physics doubt.JPG

7 years ago

Answers : (1)

Askiitians Expert Soumyajit IIT-Kharagpur
28 Points
										

Dear Siddharth,


Ans:- I think your ans is wrong why Let me explain


Let the current in the inductor is i1 and through the parallel resistor is i2


Then from kirchoff,s laws we get


10(i1+i2)+10(i1+i2)+10 i2=6..............(1)


L di1/dt =10i2


or 5 di1/dt=10i2...............(2)


Solving these two eq we get


3/5=2i1+3/2di1/dt


integrating from i1 varying from 0 to i1 we get the current through the inductance is


i1=0.3(1-exp-4t/3)


hence initially at t=0, i1=0 i.e no current flows through the inductance


So, from eq (1) we get i2=0.2 amp


Hence the current through the battery is = 0.2 amp (ans)


 


 


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All the best Siddharth!!!


 



Regards,


Askiitians Experts


SOUMYAJIT IIT_KHARAGPUR

7 years ago
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