Guest

In the circuit given in the figure the initial value of current through the battery on closing the circuit(i.e. K is pressed) is ans: 0.3 A can you please explain how?

In the circuit given in the figure the initial value of current through the battery on closing the circuit(i.e. K is pressed) is


ans: 0.3 A


can you please explain how?


832_21201_physics doubt.JPG

Grade:11

1 Answers

Askiitians Expert Soumyajit IIT-Kharagpur
28 Points
13 years ago

Dear Siddharth,

Ans:- I think your ans is wrong why Let me explain

Let the current in the inductor is i1 and through the parallel resistor is i2

Then from kirchoff,s laws we get

10(i1+i2)+10(i1+i2)+10 i2=6..............(1)

L di1/dt =10i2

or 5 di1/dt=10i2...............(2)

Solving these two eq we get

3/5=2i1+3/2di1/dt

integrating from i1 varying from 0 to i1 we get the current through the inductance is

i1=0.3(1-exp-4t/3)

hence initially at t=0, i1=0 i.e no current flows through the inductance

So, from eq (1) we get i2=0.2 amp

Hence the current through the battery is = 0.2 amp (ans)

 

 

Please feel free to post as many doubts on our discussion forum as you can. If you find any question
Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We
are all IITians and here to help you in your IIT JEE preparation.
win exciting gifts by answering the questions on Discussion Forum.

All the best Siddharth!!!

 


Regards,

Askiitians Experts

SOUMYAJIT IIT_KHARAGPUR

Think You Can Provide A Better Answer ?

ASK QUESTION

Get your questions answered by the expert for free