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Siddharth Singhania Grade: 11

In the circuit given in the figure the initial value of current through the battery on closing the circuit(i.e. K is pressed) is

ans: 0.3 A

can you please explain how?

832_21201_physics doubt.JPG

6 years ago

Answers : (1)

Askiitians Expert Soumyajit IIT-Kharagpur
28 Points

Dear Siddharth,

Ans:- I think your ans is wrong why Let me explain

Let the current in the inductor is i1 and through the parallel resistor is i2

Then from kirchoff,s laws we get

10(i1+i2)+10(i1+i2)+10 i2=6..............(1)

L di1/dt =10i2

or 5 di1/dt=10i2...............(2)

Solving these two eq we get


integrating from i1 varying from 0 to i1 we get the current through the inductance is


hence initially at t=0, i1=0 i.e no current flows through the inductance

So, from eq (1) we get i2=0.2 amp

Hence the current through the battery is = 0.2 amp (ans)



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6 years ago
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