Two cells of emf ε 1 and ε 2 (ε 2 1 ) are joined as shown in figure attached now, When a potentiometer is connected between x and y it balances for 300 cm length against ε 1 . On connecting the same potentiometer between x and z it balances for 100 cm length against ε 1 and ε 2 . Then the ratio is :

Question

Aziz Alam · Answer

According to potentiometer&rsquo; working, V 1 /V 2 =L 1 /L 2 V 1 =E 1 & V 2 =E 1 -E 2 E 1 /E 1 -E 2 =300/100 =>E 1 /E 2 =3:2

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Two cells of emf ε1 and ε2 (ε2 1) are joined as shown in figure attachednow,When a potentiometer is connected between x and y it balances for 300 cm length against ε1. On connecting the same potentiometer between x and z it balances for 100 cm length against ε1 and ε2. Then the ratio is :