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Shane Macguire Grade: upto college level
`        The dielectric strength of air is 3.0 × 10^6 V/m. A parallel-plate air-capacitor has area 20 cm^2 and plate separation 0.10 mm. Find the maximum rms voltage of an AC source which can be safely connected to this capacitor.`
3 years ago

396 Points
```										Sol. E = 3 * 10^6 V/m, A = 20 cm^2, d = 0.1 mm
Potential diff. across the capacitor = Ed = 3 * 10^6 * 0.1 * 10^-3 = 300 V
Max. rms Voltage = V/√2 = 300/√2 = 212 V

```
3 years ago
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