‘n' identical cells are joined in series with two cells A and B with reverse polarities .EMF of each cell is ‘E' and internal resistance 'r'. Calculate the potential difference across the cell A and B.

Question

‘n' identical cells are joined in series with two cells A and B with reverse polarities .EMF of each cell is ‘E' and internal resistance 'r'. Calculate the potential difference across the cell A and B.

Vikas TU · Answer

netresistance = nr net voltage in series = ne E1 = e + ir for n cells and n resitances, E2 = ne + i(nr) potential diff. E1 – E2. hence.

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‘n' identical cells are joined in series with two cells A and B with reverse polarities .EMF of each cell is ‘E' and internal resistance 'r'. Calculate the potential difference across the cell A and B.

‘n' identical cells are joined in series with two cells A and B with reverse polarities .EMF of each cell is ‘E' and internal resistance 'r'. Calculate the potential difference across the cell A and B.

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‘n' identical cells are joined in series with two cells A and B with reverse polarities .EMF of each cell is ‘E' and internal resistance 'r'. Calculate the potential difference across the cell A and B.

‘n' identical cells are joined in series with two cells A and B with reverse polarities .EMF of each cell is ‘E' and internal resistance 'r'. Calculate the potential difference across the cell A and B.

1 Answers

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