0

Guest

Courses New

A potentiometer wire 10m long and having 20 Ω resistance is connected in series with a battery and a resistance R = 2160 Ω . A Daniel cell of emf 1.08 v is balanced across the P.D. of the resistance R. The emf of thermo couple is balanced across 300 cm of the wire. The emf of thermo couple is

A potentiometer wire 10m long and having 20 Ω  resistance is connected in series with a battery and a resistance R = 2160 Ω . A Daniel cell of emf 1.08 v is balanced across the P.D. of the resistance R. The emf of thermo couple is balanced across 300 cm of the wire. The emf of thermo couple is 
 
 
 
 

Grade:12th pass

1 Answers

Eshan
askIITians Faculty 2095 Points
5 years ago
Current through the potentiometer wire=i=\dfrac{E}{20+2160}

Hence potetial difference across the potentiometer wire=(\dfrac{E}{20+2160})(20)
Therefore, emf of thermocouple=potential difference over 3m length of wire=\dfrac{3}{10}\times(\dfrac{E}{20+2160})(20)=3mV

Think You Can Provide A Better Answer ?

Other Related Questions on Electric Current

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More