A charged spherical conductor has a surface density of 0.7 C/m^2 . when it's charge is increased by 0.44 C , the charge density changes by 0.14 Cm^-2 . find the radius of the sphere

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Khimraj · Answer

As given let the radius be R then 0.44/4πR² =0.14 then R² = 11/14π and R is √(11/14π) m.Hope it clears. If u have doubts then please clearify. And if u like my answer then please approve answer

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A charged spherical conductor has a surface density of 0.7 C/m^2 . when it's charge is increased by 0.44 C , the charge density changes by 0.14 Cm^-2 . find the radius of the sphere

A charged spherical conductor has a surface density of 0.7 C/m^2 . when it's charge is increased by 0.44 C , the charge density changes by 0.14 Cm^-2 . find the radius of the sphere

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A charged spherical conductor has a surface density of 0.7 C/m^2 . when it's charge is increased by 0.44 C , the charge density changes by 0.14 Cm^-2 . find the radius of the sphere

A charged spherical conductor has a surface density of 0.7 C/m^2 . when it's charge is increased by 0.44 C , the charge density changes by 0.14 Cm^-2 . find the radius of the sphere

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