Grade 12Electric Current

The maximum current that flows through a fuse wire, before it blows out, varies with its radius 'r' as -

(a) r^3/2

(b) r

(c) r^2/3

(d) r^1/2

Please answer in detail

Anurag Kishore

16 Years agoGrade 12

5 Years ago

Option -(a) r^(3/2)

The heat produce by the fuse wire= i^2R= i^2* row*L/(π*r^2)

Now, the rate of loss of heat from the fuse wire by radiation= Emissivity* Area * Excess temp. Over surrounding=e*2πrL*theta

Before the fuse will be blown out,

The heat produce in fuse wire = rate of loss of heat from the fuse

So, i^2*row*L/(πr^2) =e*2πrL*theta

i^2 = [e*2πrL*theta*πr^2]/[row*L]

Clearly, i^2 proportion r^3

And i proportion to r^(3/2)

electric current

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electric current

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electric current

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electric current

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