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Grade 12th PassElectric Current

Star to delta convertion.

Profile image of Deepak Modi
13 Years agoGrade 12th Pass
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1 Answer

Profile image of Sher Mohammad
12 Years ago

File:Wye-delta-2.svg
R_y = \frac{R'R''}{\sum R_\Delta}

whereR_\Deltaare all impedances in the ? circuit. This yields the specific formulae

\begin{align} R_1 &= \frac{R_bR_c}{R_a + R_b + R_c} \\ R_2 &= \frac{R_aR_c}{R_a + R_b + R_c} \\ R_3 &= \frac{R_aR_b}{R_a + R_b + R_c} \end{align}

Equations for the transformation from Y-load to ?-load 3-phase circuit[edit]


R_\Delta = \frac{R_P}{R_\mathrm{opposite}}

R_P = R_1R_2+R_2R_3+R_3R_1is

\begin{align} R_a &= \frac{R_1R_2 + R_2R_3 + R_3R_1}{R_1} \\ R_b &= \frac{R_1R_2 + R_2R_3 + R_3R_1}{R_2} \\ R_c &= \frac{R_1R_2 + R_2R_3 + R_3R_1}{R_3} \end{align}



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