MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: R

There are no items in this cart.
Continue Shopping
Menu
Get instant 20% OFF on Online Material.
coupon code: MOB20 | View Course list

  • Complete Physics Course - Class 11
  • OFFERED PRICE: R 2,800
  • View Details
Get extra R 2,800 off
USE CODE: askschfd09

				   

How can a galvanometer be converted into a ammeter and voltmeter?plz explain?

5 years ago

Share

Answers : (1)

										

CONVERSION OF GALVANOMETER 
INTO AMMETER


  Since Galvanometer is a very sensitive instrument therefore it can’t measure heavy currents. In order to     convert a Galvanometer into an Ammeter, a very low resistance known as "shunt" resistance is     connected in parallel to Galvanometer. Value of shunt is so adjusted that most of the current passes     through the shunt. In this way a Galvanometer is converted into Ammeter and can measure heavy     currents without fully deflected.










VALUE OF SHUNT RESISTANCE

 
















Let resistance of galvanometer = Rg and it gives full-scale deflection when current Ig is passed through     it. Then,

Vg = IgRg -------(i)

    Let a shunt of resistance (Rs) is connected in parallel to galvanometer. If total current through the     circuit is I.



























Then current through shunt:

Is = (I-Ig)

    potential difference across the shunt:

Vs= IsRs


or 
              Vs = (I – Ig)Rs -------(ii)

    But

V=Vg
(I - Ig)Rs = IgR



CONVERSION OF GALVANOMETER INTO VOLTMETER


Since Galvanometer is a very sensitive instrument, therefore it can not measure high potential     difference. In order to convert a Galvanometer into voltmeter, a very high resistance known as "series     resistance" is connected in series with the galvanometer.


VALUE OF SERIES RESISTANCE























 Let resistance of galvanometer = Rg and resistance R(high) is connected in series to it. Then     combined resistance = (R+ Rx).


    If potential between the points to be measured = V and if galvanometer gives full-scale deflection,     when current "Ig" passes through it. Then,
 

V = Ig (Rg + Rx
V = IgR+ IgRx 
V – IgR= IgRx 
Rx = (V – IgRg)/Ig


    Thus Rx can be found.


5 years ago

Post Your Answer

Other Related Questions on Electric Current

Define ohm’s law?
 
 
Ohms law is the besic law in electric current which is given by george simon ohm, it states that when the equilibrium condition is maintained and with constant temp and pressure the...
 
Umakant biswal one year ago
 
Dear Students, We noticed that some students are copying and pasting same answer that has posted by previous users. Also, they are creating multiple account to post question and then...
 
Forum Team one year ago
 
The predominant equation which pervades the study of electric circuits is the equation ΔV = I • R In words, the electric potential difference between two points on a circuit ( ΔV ) is...
 
SAI SARDAR one year ago
What is the statement of WHEAT STONE BRIDGE?????????????????????
 
 
Gowri Sankar, Wheat stone bridge is the four arms are engaged with four resistors and one is unknown resistor.To know the resistance of unknown resistor we used the wheat stone bridge.
 
SAI SARDAR 11 months ago
 
Dear Gowri Shankar A wheat stone is a electrical circuit used to measure the an unknown electrical resistance by balancing two legs of a bridge circuit ,one leg which includes the unknown...
 
Prabhakar ch 11 months ago
 
Hello Shankar, Definition of Wheatstone bridge . : an electrical bridge consisting of two branches of a parallel circuit joined by a galvanometer and used for determining the value of an...
 
SAI SANDY 11 months ago
What are the measurements of DC AND AC CIRCUITS???????//
 
 
Gowri Sankar, The measurements of AC and DC currents in a circuit is Amperes or Coloumb per second......
 
SAI SARDAR 11 months ago
 
Hello Gowri The SI unit for measuring an electric current is the ampere, which is the flow of electric charge across a surface at the rate of one coulomb per second. Electric current is...
 
Gaddam Chethan 11 months ago
 
Hello Gowri The SI unit for measuring an electric current is the ampere, which is the flow of electric charge across a surface at the rate of one coulomb per second. Electric current is...
 
manichandra 11 months ago
what is work energy thereom...................................?
 
 
For any net force acting on a particle moving along any curvilinear path, it can be demonstrated that its work equals the change in the kinetic energy of the particle by a simple derivation...
 
rahul kushwaha 2 months ago
 
To change the kinetic energy of a particle we have to apply a force on it and the force must do work on it. This relationship between KE and WORK is called "work -energy theorem...
 
Ankur Saha 2 months ago
 
Relation bewteen KE and W: The work done on an object by a net force equals the change in kinetic energy of the object: W = KEf - KEi. This relationship is called the work-energy theorem.
 
Shreyas Patil 3 months ago
 
The amount of work done by the net force acting on a particle is equal change in it’s kinetic energy.
 
5 days ago
 
work energy therom is nothing but the total work done by all forces is equal to the change in its kinetic energy …. W=1/2 {kx 2 2 -kx 1 2 }
 
5 days ago
 
Total workdone by the Net Force on the body is equal to change in it’s kinetic energy . W total =1/2{kx 2 2 -kx 1 2 }
 
5 days ago
The cieling of long hall is 25 m high What is the maximum horizontal distance that a ball thrown with a speed of 40 ms can go without hitting the ceiling of wall? Plz explain with a DIAGRAM
 
 
Let the angle of throwing be Q with respect to the ground So, the range is R = 40*cosQ*t where t = time taken reach ground. Now, we know the time taken to reach the top of its flight is...
 
Tapas Khanda 3 months ago
 
Let the angle of throwing be Q with respect to the ground So, the range is R = 30*cosQ*t where t = time taken reach ground. Now, we know the time taken to reach the top of its flight is...
 
Tapas Khanda 3 months ago
 
Diagram is not required to solve this question. You can directly use the formula to find range : R = (v^2/g)*sin2Q Maximum height reached, H = v^2*sin^2Q/2g So, 25 = 40^2*sin^2Q/(2*9.8) So, ...
 
Tapas Khanda 3 months ago
a particle of mass m starts moving from origin along x axis and its velocity varies with position (x) as v=k√x. the work done by force acting on it during first "t" seconds is ???ans) (m k^4...
 
 
I want you to recheck your answer mr strange...you had written the value of a as k^2 ÷ 4 and you put that value at last as k^2 ÷ 2....Overall if u cann xplain it in brief i wud be...
 
Vaibhav 19 days ago
 
sry it was a mistake , this is right.......... :) …...........................................................................................
 
DR STRANGE 19 days ago
 
I dont understand how did you got (k dx)/(2√x dt).....and also this the integration of dx/√x should be x/2 but u wrote 2x how???
 
Vaibhav 19 days ago
View all Questions »

  • Complete Physics Course - Class 12
  • OFFERED PRICE: R 2,600
  • View Details
Get extra R 2,600 off
USE CODE: askschfd09

  • Complete Physics Course - Class 11
  • OFFERED PRICE: R 2,800
  • View Details

Get extra R 2,800 off
USE CODE: askschfd09

More Questions On Electric Current

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!!
Click Here for details