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A voltmeter connected in series with a resistance R1 to a circuit indicates a voltage V1 = 198V. When a series resistance R2= 2 R1 is used, the voltmeter indicates a voltage V2 = 180V. If the resistance of the voltmeter is Rv = 900 ohm, then show that the applied voltage across A and B is 220V.
let applied voltage be x V
so, by kirchoffs laws, we have :
let I1 be current in case 1 and I2 be in case 2
so acroess voltmeters , we have 198 = 900I1 . .. (1)
180 = 900I2 ... (2)
and for whole circuit, we have : x - 198 = I1(R1+900) ... (3)
x - 180 = I2(2R1+900) ... (4)
on solving eqns, 1 to 4 , we have
x = 220V
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