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anshu dutta Grade: 12
        

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7 years ago

Answers : (1)

AJIT AskiitiansExpert-IITD
68 Points
										

Dear anshu ,


Total resisitance of the circuit  = (R2 || R3) + R1


      Req  = R2 R3/R2 + R3 + R1 ;  solving we get , Req  = 3 Ω


    Now time constant of the circuit  = Req  c  =  18 ms


now apply the transient current equation ,  i  = (V/Req) (e-t / Time constant)


  we get , i  = (10/3) ( e-t/18ms)  A


now we can see that current in R2 and R3 divides equally as they are eual . so , current in R2  =  i/2


Applying joule 's heat formula  -


   Total heat dissipated  =  ∫iR2 R dt  =  ∫ (100/9 ( e-t/18ms) * 2* dt     =   (200/9)  ∫ e-2t/18ms   dt   ( limits from  0 to infi )


    =    ( 200/9) * (9 ms) =  200 mJ = 2 *106µJ

7 years ago
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