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anshu dutta Grade: 12
`        `
7 years ago

## Answers : (1)

68 Points
```										Dear anshu ,
Total resisitance of the circuit  = (R2 || R3) + R1
Req  = R2 R3/R2 + R3 + R1 ;  solving we get , Req  = 3 Ω
Now time constant of the circuit  = Req  c  =  18 ms
now apply the transient current equation ,  i  = (V/Req) (e-t / Time constant)
we get , i  = (10/3) ( e-t/18ms)  A
now we can see that current in R2 and R3 divides equally as they are eual . so , current in R2  =  i/2
Applying joule 's heat formula  -
Total heat dissipated  =  ∫iR2 R dt  =  ∫ (100/9 ( e-t/18ms)2  * 2* dt     =   (200/9)  ∫ e-2t/18ms   dt   ( limits from  0 to infi )
=    ( 200/9) * (9 ms) =  200 mJ = 2 *106µJ
```
7 years ago
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