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```
When a currentof 2Aflows in a batteryfromnegative to positive terminal, thepotential difference across
it is 12V. If a current of 3Aflowing in the opposite direction produces a potential difference of 15V, the
EMF of the battery is
(A) 12.6 V (B) 13.2 V (C) 13.5 V (D) 14.0 V
```
7 years ago

68 Points
```										                                                                                                                                                                                                                                                            Dear   LILAMAYA MISHRA,As the voltage developed across the battery depends upon the direction of current there will be an internal resistance in the battery which probably you might be missing. take that to be r ,  let the EMF of the battery to be E ,
writing equations ,
- to +  flow of current  INSIDE THE BATTERY -----   E - 2 *r =12
+to -  flow of current ------    E + 3 * r =15
solve the equations ---
E =13.2 V
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```
7 years ago
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