Calculate Equivalent Resistance Across AB and ADResistance

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how are current and current density related?
when the cross sectional area approaches zero current density is same as current. sher mohammad faculty askiitians, iit delhi
Sher Mohammad one month ago
sir which chapters are important, read this article and other similar articles all good important chapter are mentioned in this chapter.
Sher Mohammad one month ago
What is thevenin's theorem
Any combination of batteries and resistances with two terminals can be replaced by a single voltage source e and a single series resistor r . The value of e is the open circuit voltage at...
Mukesh Sharma 6 months ago
Thevenin`s Theorem states that it is possible to simplify any linear circuit, no matter how complex, to an equivalent circuit with just a single voltage source and series resistance...
Amit Sinha 6 months ago
A solid sphere uniformly charged has a long smooth tunnel passing through it, at a distance of r from the centre of the sphere(assume it to be a chord). A charged particle -Q,mass m is...
Distance of chord from center = r Radius of Sphere = R Distance of particle from center of tunnel = x Distance of particle from center Now the electric field effective on that particle will...
Arun Kumar 2 months ago
I want these questions to be solved E is directed along x,y and z axes and is equal to 2i^+2j^+2k^. displacement vector fo(1,1,1) is i^+j^+k^. take dot product of E and d with negative will obtain a p.d of 6 V...
siddharth gupta 2 months ago
mathematically ∂V/∂x=-Ky and ∂V/∂y=-Kx i.e E=-(-K(y i+ x j ))=K(y i +x j)​ magnitude of E=K(x 2 +y 2 ) 1/2 =Kr. it is same as explanation provided above and is only its mathematical part.
siddharth gupta 2 months ago
Please answer all
Abhinav Saurabh 2 months ago
A particle on a stretched string supporting a travelling wave, takes 5.0 ms to move from its mean position to the extreme position. The distance between two consecutive particles, which are...
Sol. Time period, T = 4 * 5 ms = 20 * 10–3 = 2 * 10–2 s λ = 2 * 2 cm = 4 cm frequency, f = 1/T = 1/(2 * 10–2) = 50 s–1 = 50 Hz Wave speed = λ f = 4 * 50 m/s = 2000 m/s = 2 m/s
Jitender Pal 2 months ago
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