Calculate Equivalent Resistance Across AB and ADResistance

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how are current and current density related?
 
 
when the cross sectional area approaches zero current density is same as current. sher mohammad faculty askiitians b.tech, iit delhi
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Sher Mohammad one month ago
sir which chapters are important
 
 
http://www.askiitians.com/iit-study-material/iit-jee-mathematics/, read this article and other similar articles all good important chapter are mentioned in this chapter.
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Sher Mohammad one month ago
What is thevenin's theorem
 
 
Any combination of batteries and resistances with two terminals can be replaced by a single voltage source e and a single series resistor r . The value of e is the open circuit voltage at...
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Mukesh Sharma 6 months ago
 
Thevenin`s Theorem states that it is possible to simplify any linear circuit, no matter how complex, to an equivalent circuit with just a single voltage source and series resistance...
 
Amit Sinha 6 months ago
A solid sphere uniformly charged has a long smooth tunnel passing through it, at a distance of r from the centre of the sphere(assume it to be a chord). A charged particle -Q,mass m is...
 
 
Distance of chord from center = r Radius of Sphere = R Distance of particle from center of tunnel = x Distance of particle from center Now the electric field effective on that particle will...
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Arun Kumar 2 months ago
I want these questions to be solved
 
 
16.here E is directed along x,y and z axes and is equal to 2i^+2j^+2k^. displacement vector fo(1,1,1) is i^+j^+k^. take dot product of E and d with negative sign.you will obtain a p.d of 6 V...
 
siddharth gupta 2 months ago
 
mathematically ∂V/∂x=-Ky and ∂V/∂y=-Kx i.e E=-(-K(y i+ x j ))=K(y i +x j)​ magnitude of E=K(x 2 +y 2 ) 1/2 =Kr. it is same as explanation provided above and is only its mathematical part.
 
siddharth gupta 2 months ago
 
Please answer all
 
Abhinav Saurabh 2 months ago
A particle on a stretched string supporting a travelling wave, takes 5.0 ms to move from its mean position to the extreme position. The distance between two consecutive particles, which are...
 
 
Sol. Time period, T = 4 * 5 ms = 20 * 10–3 = 2 * 10–2 s λ = 2 * 2 cm = 4 cm frequency, f = 1/T = 1/(2 * 10–2) = 50 s–1 = 50 Hz Wave speed = λ f = 4 * 50 m/s = 2000 m/s = 2 m/s
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Jitender Pal 2 months ago
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