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A box contains 5 black, 4 white and 6 red balls. Two balls are drawn simultaneously without replacement . Then 1) the probability that the first will be white and the second will be black 2)probability that the first will be black and second will be white 3) the probability that either of the two balls is a) white b) black c)red 4) the probability that the first is white second is other than white 5) the probability that first is white second is other than black6) all the above cases with the replacement of balls

A box contains 5 black, 4 white and 6 red balls. Two balls are drawn simultaneously without replacement . Then 1) the probability that the first will be white and the second will be black 2)probability that the first will be black and second will be white 3) the probability that either of the two balls is a) white b) black c)red 4) the probability that the first is white second is other than white 5) the probability that first is white second is other than black6) all the above cases with the replacement of balls

Grade:12

1 Answers

Sourabh Singh IIT Patna
askIITians Faculty 2104 Points
8 years ago
Try to write down events in terms of statement and then apply the probability.

1)(4 *5)/15*15.

Similarly you can do the others.In case of doubt ask on forum again

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