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```         the bob of a pendulum is released from horizontal posn a.if the lengthof pendulum is 1.5 m what is the speed with which the bob arrives at lowermost point b, given that it dissipated 5% of its energy against air resistance?
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7 years ago

147 Points
```										Dear manisha
initial energy of bob = mg*1.5
energy dissipated = 5/100 * (mg*1.5)

now energy balane
mg*1.5 = 1/2 m v2 + 5/100 * (mg*1.5)
v2 =3g - 3g/20
v2 =57g/20
v= √(57g/20)
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```
7 years ago
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