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manisha mehra Grade: 11
        

 the bob of a pendulum is released from horizontal posn a.if the lengthof pendulum is 1.5 m what is the speed with which the bob arrives at lowermost point b, given that it dissipated 5% of its energy against air resistance?


 

7 years ago

Answers : (1)

Badiuddin askIITians.ismu Expert
147 Points
										

Dear manisha


initial energy of bob = mg*1.5


energy dissipated = 5/100 * (mg*1.5)




now energy balane


 mg*1.5 = 1/2 m v2 + 5/100 * (mg*1.5)


 v2 =3g - 3g/20


v2 =57g/20


v= √(57g/20)


   
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7 years ago
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