Grade 12Discuss with colleagues and IITians

two circles x2+y2-6x+8=0 and x2+y2-6=0 are given.The eqn. of circle through their point of intersection and (1,1) is?

please explain!!!!

i will surely approve

pratiksha agarwal

13 Years agoGrade 12

5 Answers

Ashwin Muralidharan IIT Madras

Approved Tutor Answer13 Years ago

On solving,

You should be getting k = -1/2

and eqaution of circle as x^2 + y^2 - 3x + 1 = 0.

Regards,

Ashwin (IIT Madras).

FITJEE

Approved Tutor Answer13 Years ago

step1----

get the two intersection ofthe two circles by solving the two equations.

step 2---- now U got three pts from where that circle is passing i.e. two intersectn points+(1,1).

step3----

use the formula----

(x-x1)(x-x2)+(y-y1)(y-y2)=0

and pass it from third one.

where,

(x1,y1)

(x2,x3)

(x3,y3)

are the three points from where the circle is passing.

Vikas TU

Approved Tutor Answer13 Years ago

eqn. of circle through their point of intersectionis the case of the family of circles.

and the condiotion is =

S1 + KS2 = 0

WHERE S1 and S2 = eqn. of circles

and k is any constant.

Thus,

(x2+y2-6x+8) + k(x2+y2-6) = 0......................................(1)

Now pass the points (1,1) in the eqn. (1)

U will get the value of K.

After then put the value of k again and get the eqn. of circle.

somy chaturvedi

Approved Tutor Answer13 Years ago

x^2+y^2-3x+1=0.if i am right then i willl send u the solution

FITJEE

13 Years ago

step1----

get the two intersection ofthe two circles by solving the two equations.

step 2---- now U got three pts from where that circle is passing i.e. two intersectn points+(1,1).

step3----

use the formula----

(x-x1)(x-x2)+(y-y1)(y-y2)=0

and pass it from third one.

where,

(x1,y1)

(x2,x3)

(x3,y3)

are the three points from where the circle is passing.